If it's not what You are looking for type in the equation solver your own equation and let us solve it.
14x+2x^2=156
We move all terms to the left:
14x+2x^2-(156)=0
a = 2; b = 14; c = -156;
Δ = b2-4ac
Δ = 142-4·2·(-156)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-38}{2*2}=\frac{-52}{4} =-13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+38}{2*2}=\frac{24}{4} =6 $
| -9s=-10s-20 | | 13h=8+14h | | 4|2-6x|=3x+4 | | -4x+8(x-2)=8 | | -8=2(y+6)+2y | | 28=7(n-8)-8(5-3n) | | (z+3)^2=-16 | | 9=-8u+5(u-3) | | 49=53+x | | 8=x/2−4 | | 4(3y-5)=2(3y-4) | | 0.9=0.6r-0.9 | | 4x-4x=2x+2 | | 5(a-7)=9(3) | | 0.4x0.93= | | 6+1-2x+5x=-x-7 | | 2.5b=45 | | 7(7-5)+3y=10(y+1) | | Z=x*Y3 | | 99=3(-2-5a) | | x/(18.91+x)=0.3 | | x-3-10=-5 | | v=(6+-8)(12) | | 18/5=x/5 | | 1.41-7.9t=-9.3t-9.93 | | −2(−4n+1)+5(25n−8)=−62 | | 231=-y+128 | | 231=-y | | 80=-y+196 | | -2-9b=-8b-10 | | 5/2-2g=5/2g-3+9 | | x(18.91+x)=0.3 |